SOLUTION: Simplifying a product of radical expressions. (2 square root of 3-3 square root of 10) (6 square root 10-3 square root of 3) 3x+3x+9xyz=z

Question 49918: Simplifying a product of radical expressions.
(2 square root of 3-3 square root of 10) (6 square root 10-3 square root of 3)
3x+3x+9xyz=z
Answer by ilana(307) (Show Source): You can put this solution on YOUR website!
I am going to use the notation "rt" for "square root of", so the problem is (2rt3-3rt10)(6rt10-3rt3). Now, we use the FOIL method, or any method of multiplying binomials. If it is confusing for you to use radicals, you can pretend the rt3 and rt10 are variables, like x and y. So you get 12rt3rt10 - 6rt3rt3 - 18rt10rt10 + 9rt10rt3. rt3rt10 = rt10rt3 = rt30, rt3rt3=3, and rt10rt10=10, so we get 12rt30-18-180+9rt30, so the final answer is 21rt30-198.
RELATED QUESTIONS
Combine and Simplify: 2(square root of)18 - (square root of)27 + (square root of)32 a) (answered by funmath)

-3* square root of 2 over square root of... (answered by persian52)

(3 square root of 6)(2 square root... (answered by checkley77)

1. 4 square root 16x^5y^6 2. (square root 3x + 1)^2 3. 10 / 1- square root of 6 (answered by lynnlo)

Square root of -3 (answered by jim_thompson5910)

(3+square root of 5)squared=(3+square root 5)(3+square root 5) (answered by tns_tutor5000)

multiply and simplify. show your steps. 1. square root of 15b 2. square root of 5(2... (answered by drk,Alan3354)

simplify each radical expression: 10. square root of 4n^3 (answered by tommyt3rd)

square root of 3 over square root of 11+2 10- square root of 3 over 10+ square root of (answered by tommyt3rd)