SOLUTION: Truth Table: ~(P=>Q)<=>(P^~Q)
I believe I am on the right path with the following:
P Q P=>Q ~(P=>Q) ~Q P^~Q
t t t t f t
f t t
Algebra.Com
Question 385135: Truth Table: ~(P=>Q)<=>(P^~Q)
I believe I am on the right path with the following:
P Q P=>Q ~(P=>Q) ~Q P^~Q
t t t t f t
f t t f f f
t f f t t t
f f t f t f
Making this table a neither a tautology or a contrdiction. Would this be correct? Six columns with 4 t or f under each column. They would not line up for me so I hope this is understandable.
Melody
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
The truth table for ~(P=>Q)<=>(P^~Q) is
| P | Q | P => Q | ~(P => Q) | ~Q | P ^ ~Q | ~(P => Q) <=> (P ^ ~Q) | | T | T | T | F | F | F | T |
| T | F | F | T | T | T | T |
| F | T | T | F | F | F | T |
| F | F | T | F | T | F | T |
which means that we have a tautology (because the last column has nothing but T in it).
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
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