You can
put this solution on YOUR website!The operator between p and ~q is not showing in my browser. So I am going to use "@" for the operator in the problem and "$" for the complementary operator. For example, if your operator is set union then "@" stands for this and "$" stands for set intersection.
According to DeMorgan's law
~(p @ ~q) = ~p $ ~~q = ~p $ q
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