You can
put this solution on YOUR website!truth table for not(pandq)
Remember conjunction is true only if both statements true
not p is opposite of p (that "not p" is false,, if "p" is true,,, and viseversa)
p,,,,q,,,,notp,,,,nptq,,,,not(pandq)
t,,,,t,,,,,f,,,,,,,,,,,f,,,,,,,,,,,,,,f
t,,,,f,,,,,f,,,,,,,,,,,t,,,,,,,,,,,,,,f
f,,,,t,,,,,t,,,,,,,,,,,f,,,,,,,,,,,,,,f
f,,,,f,,,,,t,,,,,,,,,,,t,,,,,,,,,,,,,,t