SOLUTION: Find the center and radius of the circle: x^2+y^2-4x+10y-3=0
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Question 991385: Find the center and radius of the circle: x^2+y^2-4x+10y-3=0
Found 4 solutions by Fombitz, josgarithmetic, ikleyn, Timnewman:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Center : (,)
Radius :
.
Answer by josgarithmetic(39616) (Show Source): You can put this solution on YOUR website!
Complete the Squares and put into standard form.
See this lesson for Completing the Squares, and do for both the x and the y.
http://www.algebra.com/my/Completing-the-Square-to-Solve-General-Quadratic-Equation.lesson?content_action=show_dev
Circle Equation Standard Form is and the center is (h,k), and size of radius is r.
Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website!
.
Find the center and radius of the circle: x^2+y^2-4x+10y-3=0
-----------------------------------------------------------------
= ,
Transform to an equivalent expression by completing full squares:
= ,
= ,
= .
It is the circle of the radius r = = with the center at the point (2,-5).
Answer by Timnewman(323) (Show Source): You can put this solution on YOUR website!
Hi dear,
Comparing
x²+y²-4x+10y-3=0 with the general form of equation of a circle;x²+y²+2gx+2fy+c=0
From the above,
2g=-4
g=-2,
also,
2f=10
f=5
The centre of the
circle is (2,-5).
Also,
r²=g²+f²-c
r²=2²+5²-(-3)
r²=4+25+3
HOPE THIS HELPS?
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