SOLUTION: In a quadltrl ab=ad=10 and BC=CD=5. What is value of angle BAD?(Without trigonometry)

Question 981938: In a quadltrl ab=ad=10 and BC=CD=5. What is value of angle BAD?(Without trigonometry)

Answer by ed42ptt(4) (Show Source): You can put this solution on YOUR website!
Let me start this with AB = AD = 10 and BC = CD = 5
Prove AB = AD > BC = CD
If AB = AD and BC = CD then ACD = ABC => A(CD) = (AB)C => A(C)D = A(BC) =>
A(5) = (10)C => (10)C = (5)A => C = 5/10A => C = 1/2A thus 2C = A
(2C)B = (2C)D = 2(CB) = 2(CD) => Since A = 2C and BAD = B(2C)D =>
BC(2D) => BAD =>(5)(2)D = 10D => BAD => B(10) => BAD thus 10D = 10B = BAD and
D = B => BA = AD = 10 then B = 1 and D = 1 thus BAD = 10 because (1)(10) = 10
End line
Shape of a kite, boomerang, or a crossed quadrilateral
Not sure whether I did it correctly so let me know if this is what it should have been or not.
ED

RELATED QUESTIONS
in a trapezium, AB is parallel to DC AND AD=BC and AD= 10cm CD =20 cm BC=10 cm and AB=x... (answered by greenestamps)

1. Given:AB=(3x-5)cm,BC=(2y-7)cm,CD=(X+7)cm and AD=(y+3)cm. a.what is the value of x?... (answered by mananth,ikleyn)

In △ABC, m∠CAB = 60� and point D∈BC so that AD=10 in and the distance... (answered by greenestamps)

▱ upper left: A lower left: D Upper right: B lower right: C Centre: E 1.)... (answered by CPhill)

Prove : that triangle ABC is Isosceles. Where AD __l__ BC Can you tell me where I went (answered by Edwin McCravy)

I have no idea how to post an image, but I was able to find an exact image on another... (answered by Edwin McCravy)

A triangle ABC, where |AB| = |AC|, a line CD is drawn from angle C and intersects side AB (answered by CPhill,greenestamps,ikleyn,math_tutor2020)

Triangle ABC has AB = 6. Let D lie on BC such that \overline{AD} bisects \angle BAC. If... (answered by CPhill,ikleyn,greenestamps)

In △ABC, m∠CAB = 60� and point D ∈ BC so that AD = 10 in, and the... (answered by ikleyn)