SOLUTION: Given the equation of the circle is {{{x^2-4x+y^2-6y=3}}}. Find the equation of the circle in the form{{{(x-a)^2+(y-b)^2=r^2}}}. Hence find out the centre, area and circumference o
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Question 975231: Given the equation of the circle is . Find the equation of the circle in the form. Hence find out the centre, area and circumference of the circle.
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Given the equation of the circle is .
x^2-4x + 4 + y^2-6y+9 = 3 +4+9
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(x-2)^ + (y-3)^2 = 16
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Find the equation of the circle in the form.
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Hence find out the
centre:: (2,3)
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area = pi*4^2 = 16pi square units
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circumference of the circle = 2*pi*4 = 8pi units
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Cheers,
Stan H.
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Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
in form
......complete squares
so, , , and
the center is at (,)
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