SOLUTION: find equation of the circle that has radius of 5 and tangent to the line 3x+4y=24 at the point (2, 4 1/2) the answer is 4x^2+4y^2+8-4y-95=0 or 4x^2+4y^2-40x-68y+289=0 please

SOLUTION: find equation of the circle that has radius of 5 and tangent to the line 3x+4y=24 at the point (2, 4 1/2) the answer is 4x^2+4y^2+8-4y-95=0 or 4x^2+4y^2-40x-68y+289=0 please

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Question 949360: find equation of the circle that has radius of 5 and tangent to the line 3x+4y=24 at the point (2, 4 1/2)
the answer is 4x^2+4y^2+8-4y-95=0 or 4x^2+4y^2-40x-68y+289=0
please tell me how did it come up to those answers.
thank you
Answer by josgarithmetic(39621) (Show Source): You can put this solution on YOUR website!
Mistake made in solution, so removed.
(Final results in email message)
(Results in standard form can be reworked into general form)
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