Question 941799: Find the equaton of the circle with radius 6 and whose center lies at the intersection of the lines 3x+y=1 and -2x-3y=4 Answer by srinivas.g(540) (Show Source): You can put this solution on YOUR website! equation of circle in standard form:
where center =(h,k) , radius =r
center lies at the intersection of the lines 3x+y=1 and -2x-3y=4
3x+y =1......eq(1)
-2x-3y =4........eq(2)
Solve: We'll use substitution. After moving 1*y to the right, we get: , or . Substitute that
into another equation: and simplify: So, we know that y=-2. Since , x=1.
Answer: .
(x,y)=(1,-2)
center(h,l)= (1,-2)
equation circle becomes
Result :