SOLUTION: Give the center of the circle with equation x^2+2x+y^2+22=0 I’ve come up with the answer to be (-1,0) is this right?

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Question 92916: Give the center of the circle with equation x^2+2x+y^2+22=0
I’ve come up with the answer to be (-1,0) is this right?

Found 2 solutions by psbhowmick, chitra:
Answer by psbhowmick(489) (Show Source):
You can put this solution on YOUR website!

So centre is at (-1, 0).
You are right!

Answer by chitra(359) (Show Source):
You can put this solution on YOUR website!
The given equation of the circle is:

Rearranging terms and completing the square, we get:

Comparing the above equation with the standard eequation of the circle, we get:

where (h,k) forms the centre and r the radius.

so here on comparing, we find (h,k) = (-1,0)

Thus the solution..

Regards