SOLUTION: (x+1)^2 + (y+6)^2=16
Algebra.Com
Question 921582: (x+1)^2 + (y+6)^2=16
Found 2 solutions by Alan3354, MathLover1:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Do you have a question?
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
as your Question 921580:
again,
recall equation of a circle in standard form:
where is the radius of the circle, and (,) are the coordinates of its center
..so, here you have a circle with center at (, and radius
RELATED QUESTIONS
y=-2x-1
y=3x-16
-2x-1=3x-16
-1=5x-16
15=5x
3=x... (answered by stanbon)
(x^2)/(4)+(y^2)/(16)=1 (answered by lwsshak3)
(x+3)2 + (y-1)2 =... (answered by solver91311)
X^2/25+y^2/16=1 (answered by ewatrrr)
(X-3)^2+(y+1)^2=16 (answered by ewatrrr)
X^2/16 +... (answered by ikleyn)
Y=2... (answered by Fombitz)
solve with substitutions:
-2 x + 1 y = 10 .............1
1 y = -6 -2 x ---------2 (answered by mananth)
y=x+6... (answered by josgarithmetic)