SOLUTION: Find the points of intersection of the circles: x^2 + y^2-2x-2y-2=0 and x^2+y^2+2x+2y-2=0. Draw the circles
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Question 893015: Find the points of intersection of the circles: x^2 + y^2-2x-2y-2=0 and x^2+y^2+2x+2y-2=0. Draw the circles
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
x^2 + y^2-2x-2y-2=0 and x^2+y^2+2x+2y-2=0
The symmetry of this system indicates that intersections should occur on the line .
(-1,1) and (1,-1) work as the intersections.
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