SOLUTION: A point on the circumference of the circle with the equation (x+10)^2+(y+1)^2=25 is what?
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Question 886690: A point on the circumference of the circle with the equation (x+10)^2+(y+1)^2=25 is what?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A point on the circumference of the circle with the equation (x+10)^2+(y+1)^2=25 is what?
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The center is (-10,-1)
The radius is sqrt25 = 5
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One of the points of the circle must be (-15,-1)
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Do you agree?
Cheers,
Stan H.
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