SOLUTION: Find the equations of the tangents to (x-2)^2 + (y+3)^2 =16
a) parallel to the y-axis
b)parallel to the x-axis
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Question 878422: Find the equations of the tangents to (x-2)^2 + (y+3)^2 =16
a) parallel to the y-axis
b)parallel to the x-axis
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The graph is a circle centered at )
with radius 4.
The two tangents parallel to the 
-axis are 
and 
The two tangents parallel to the 
-axis are 
and 
John
My calculator said it, I believe it, that settles it
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