SOLUTION: Write the standard equation of a circle with center (6, 0) that passes through the point (0, 0). a x2 + y2 = 25 b (x + 6)2 + y2 = 36 c (x

SOLUTION: Write the standard equation of a circle with center (6, 0) that passes through the point (0, 0). a x2 + y2 = 25 b (x + 6)2 + y2 = 36 c (x - 6)2 + y2 = 25 d (x -

Question 876359: Write the standard equation of a circle with center (6, 0) that passes through the point (0, 0).
a
x2 + y2 = 25
b
(x + 6)2 + y2 = 36
c
(x - 6)2 + y2 = 25
d
(x - 6)2 + y2 = 36
e
x2 + y2 = 36
f
(x + 6)2 + y2 = 25

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Standard Form of an Equation of a Circle is
where Pt(h,k) is the center and r is the radius
radius must be 6 IF circle passes thru (0,0)

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