SOLUTION: What is the correct standard equation of a circle with center (5, -1) and radius 12? a (x + 5)2 + (y - 1)2 = 144 b (x + 5)2 + (y

SOLUTION: What is the correct standard equation of a circle with center (5, -1) and radius 12? a (x + 5)2 + (y - 1)2 = 144 b (x + 5)2 + (y - 1)2 = 12 c (x � 5)2 + (y + 1)2 = 1

Question 876334: What is the correct standard equation of a circle with center (5, -1) and radius 12?
a
(x + 5)2 + (y - 1)2 = 144
b
(x + 5)2 + (y - 1)2 = 12
c
(x � 5)2 + (y + 1)2 = 144
d
(x � 5)2 + (y + 1)2 = 12
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
circle with center (5, -1) and radius 12
c. (x � 5)^2 + (y + 1)^2 = 144
Need to Know
Standard Form of an Equation of a Circle is
where Pt(h,k) is the center and r is the radius

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