SOLUTION: which point lies outside the circle with equation (x-2)^2 + (y+3)^2 =4 ?

SOLUTION: which point lies outside the circle with equation (x-2)^2 + (y+3)^2 =4 ?

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Question 875493: which point lies outside the circle with equation (x-2)^2 + (y+3)^2 =4 ?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
circle: (x-2)^2 + (y+3)^2 =4

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