SOLUTION: What is the center and radius of x^2 + y^2 - 14y + 48 = 0

SOLUTION: What is the center and radius of x^2 + y^2 - 14y + 48 = 0

Algebra.Com

Question 870613: What is the center and radius of x^2 + y^2 - 14y + 48 = 0

Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!

Center is (0,7) and radius is 1.
RELATED QUESTIONS
What is the center and the radius of a circle whose equation is x^2+y^2 -4x +14y +28=0... (answered by lwsshak3)

find the ratius and center of the circle:... (answered by lwsshak3)

What is the center of the circle given by the equation x^2 + y^2 - 10x + 14y+ 10 =0 (answered by MathLover1)

What is the center and radius of the circle with the given equation? (x � 1)^2 + (y +... (answered by AnlytcPhil)

Write the equation of the circle in standard form. Find the center , radius, intercepts,... (answered by stanbon)

Write the equation of the circle in standard form. Find the center, radius, intercepts,... (answered by Alan3354)

What is the center and the radius of the circle:... (answered by lwsshak3)

What is the center and radius of the circle with equation... (answered by funmath)

what is the center and radius of the equation below?... (answered by rapaljer)