SOLUTION: find the equation of circle passes through the points (3,7) ,(5,5) and has its center on the x-4y=1

Question 850088: find the equation of circle passes through the points (3,7) ,(5,5) and has its center on the x-4y=1
Answer by josgarithmetic(39623) (Show Source): You can put this solution on YOUR website!

The center of the circle is some unknown point on the blue line, and the small almost stray-like marks are the locations of the given points to be contained on the circle.

The points on the line are variables in the form of ordered pairs, (x, x/4-1/4). All points on a circle are equidistant from the center, so we can apply the distance formula for this center and each of the given circle's points.

and expect from this to perform some algebraic steps to reach a solution for x, and then just use it to compute y; and you have the center point for the circle. The steps are omitted here because of the time length to type in all the text.
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Result is x=-3, and y=-1; for the center of (-3,-1).
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The radius for the circle can now be found using this found center point and either of the given points.
radius,
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The circle's equation is .
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