Hi,

(6,-6) (3,-7) (3,3). 

(3,-7) (3,3)  ⇒ x = 3   and as -7 + 3 = 10, c = 5

 ⇒     as 3-(-2) = 5

 



 

Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
 A circle that passes through both (3,-7) (3,3) has a diameter of 10  (7+3), radius of 5 and centre at (3, -2) since  -7+5=-2 and 3-5=-2



(x-3)^2+(y+2)^2 = 25

 

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