SOLUTION: Find the point of intercept to the tangent of a circle at (x^2 y^2-2x 3y=14 and x^2 y^2 3x 6y=24)

SOLUTION: Find the point of intercept to the tangent of a circle at (x^2 y^2-2x 3y=14 and x^2 y^2 3x 6y=24)

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Question 846575: Find the point of intercept to the tangent of a circle at (x^2 y^2-2x 3y=14 and x^2 y^2 3x 6y=24)
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Your equations are not equations of circles if that's what you intended.
Your second equation doesn't even have any operators between the terms.
Please check your equations and repost.
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