SOLUTION: Find the center and radius of the circle x^2+y^2-8x-10y+32=0
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Question 845586
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Find the center and radius of the circle x^2+y^2-8x-10y+32=0
Answer by
ewatrrr(24785)
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Hi,
(x-4)^2 +(y-5)^2 = -32 + 16 + 25 = 9
(x-4)^2 +(y-5)^2 = 3^2, C(4,5) and r = 3
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