SOLUTION: How many grams of O2 gas would occupy a 400.0 liter container when the temperature is 300.0 K and the pressure is 2.20 atm

Question 824205: How many grams of O2 gas would occupy a 400.0 liter container when the temperature is 300.0 K and the pressure is 2.20 atm
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
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the ideal gas law:
PV = nRT
where:
P = pressure atm
V = volume liter
n = amount of substance (mol)
R = gas constant = 0.082057 (L*atm/(mol*K)
T = temp (kelvin)
---
PV = nRT
n = PV/(RT)
n = (2.2 * 400)/(0.082057 * 300)
n = 35.747508845477334 mol
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the atomic mass of O is 15.9994 but we have two atoms of oxygen (O2):
O2 weighs 15.9994 * 2 = 31.9988 g/mol
---
weight of O2:
31.9988 g/mol * 35.747508845477334 mol
1143.877386044660170
---
answer:
about 1143.9 grams of O2
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