SOLUTION: Write an equation of the line tangent to the circle given by (x^2 + y^2 - 6x - 4y + 8 = 0) at the point (5,3) in slope intercept form.

Question 817055: Write an equation of the line tangent to the circle given by (x^2 + y^2 - 6x - 4y + 8 = 0) at the point (5,3) in slope intercept form.
Answer by josgarithmetic(39621) (Show Source): You can put this solution on YOUR website!
Completing the Squares for the circle gives its standard form as .
The center point of this circle is then (3,2).

The point on the circle, (5,3) and the center of circle, (3,2) form a slope of , one half. The tangent line to point (5,3) must be .

This tangent line, starting with point-slope form, is . Simplify it and put into slope intercept form.
RELATED QUESTIONS
Given a circle: (x-4)^2 + (y+5)^2 = 5, find the equation of the line (in slope-intercept... (answered by josmiceli)

Write the general and standard form of the equation of the circle satisfying the given... (answered by Alan3354)

A line is tangent to the circle whose equation is x^+y^+6x-6y-2=0 at the point (1,5).... (answered by venugopalramana)

Find the equation of the line tangent to the circle at the indicated point.... (answered by MathLover1,ikleyn)

What is the equation of the line that is tangent (at point (6,2)) to the circle defined... (answered by Alan3354)

1. Determine the slope and the y-intercept of the graph of the equation. 12x + y + 5 = (answered by ReadingBoosters)

how do i find the equation of the line tangent to the circle x^2+y^3=13 at the point... (answered by mananth)

Given a line with equation 6x-y=5. Write an equation in point-slope form of the line... (answered by Cromlix)

Given a line with equation 6x-y=5. Write an equation in point-slope form of the line... (answered by josgarithmetic)