SOLUTION: What is the general form of the equation of the given circle with center A?
A(-3,12) r=5
Algebra.Com
Question 801792: What is the general form of the equation of the given circle with center A?
A(-3,12) r=5
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
(x - a)^2 + (y - b)^2 = r^2
(x + 3)^2 + (y - 12)^2 = 25
= x^2 + y^2 + 6x - 24y + 128 = 0
Hope this helps.
:-)
RELATED QUESTIONS
What is the general form of the equation of the given circle with center (-3,12) and the... (answered by nerdybill)
Given the center: (3, -5) and r = 3
What is the center-radius form of the equation?... (answered by Fombitz)
write the standard form of the equation of a circle with center (-3,5), given... (answered by Sarah900)
Hello. What is the standard and general form of the equation of a circle with a center at (answered by josgarithmetic)
What is the general form of the equation of a circle with its center at (-2, 1) and... (answered by Fombitz)
What is the general form of the equation of a circle with its center at (-2, 1) and... (answered by stanbon)
Write the standard form of the equation and the general form of the equation of the... (answered by Alan3354)
he general form of the equation of a circle is x2+y2+2x−6y+1=0.
What are... (answered by Boreal)
What is the equation of a circle in general form whose center is at (-3,-4) and passes... (answered by math-vortex)