SOLUTION: Please help me!! I do not understand how to do this question!
The equation of he circle is x^2 + y^2 = 6*x + 8*y -24 = 0. Find the equation of the diameter of the circle which p
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-> SOLUTION: Please help me!! I do not understand how to do this question!
The equation of he circle is x^2 + y^2 = 6*x + 8*y -24 = 0. Find the equation of the diameter of the circle which p
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Question 800482: Please help me!! I do not understand how to do this question!
The equation of he circle is x^2 + y^2 = 6*x + 8*y -24 = 0. Find the equation of the diameter of the circle which passes through the point (-1,1).
Please help me!! I do not understand this question, how do I do it?!
Thank you! Answer by mananth(16949) (Show Source):
x^2-6x+9 +y^2+8y+16=24+9+16
(x+3)^2+(y+4)^2=49
center =(3,-4)
The other point is (-1,1)
Find the equation of line passing through (-1,1) and (3,-4)
(y-1)/(1+4) =(x-(-1))/(-1-3)
