SOLUTION: The equation of a circle and a point on it are given. Find the equation of the tangent at that point
a) x^2 + y^2 = 10 (1,-3)
b) x^2 + y^2 = 4 (√2, √2)
Can you pleas
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Question 795645: The equation of a circle and a point on it are given. Find the equation of the tangent at that point
a) x^2 + y^2 = 10 (1,-3)
b) x^2 + y^2 = 4 (√2, √2)
Can you please help me out? Thank you so much in advance:)
Can you also please show the steps it would really help me understand:)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The equation of a circle and a point on it are given. Find the equation of the tangent at that point
a) x^2 + y^2 = 10 (1,-3)
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2xdx + 2ydy = 0
xdx = -ydy
dy/dx = -x/y (for any point on a circle)
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m @ (1,-3) = 1/3
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Use y = mx + b and the point to find b
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