SOLUTION: I need your help The equation of a circle with radius is (x-h)^2+ (y-k)^2 if the center is at (h,k) Find the condition that a circle shall a. touch the x-axis b.have its center

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Question 771657: I need your help
The equation of a circle with radius is (x-h)^2+ (y-k)^2 if the center is at (h,k) Find the condition that a circle shall
a. touch the x-axis
b.have its center on the y-axis
c.touch both axes
d.have its center on the line 3x+4y=12

Answer by KMST(5328)   (Show Source): You can put this solution on YOUR website!
The equation of a circle with radius is if the center is at

Each of the conditions sets (fixes) something about , and , but one or two of those variables will still be free to take any value. The un-fixed variable(s) will still be in the equation, and the equation will represent an infinite number of circles.

a. If the circle touches the x-axis (is tangent to the x-axis), the center is at a distance from the x-axis, at point
so the equation is

b. If the circle has its center on the y-axis (which is the line , the center is at and the equation is


c. If the circle touches both axes, the center is at a distance from both axes, at point and the equation is


d. If the circle has its center on the line ,
then
--> --> -->
and the equation gets ugly:

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