SOLUTION: Two parallel chords on opposite sides of the centre of a circle are 9 cm apart. If the chords are 8 cm and 12 cm long, then what is the radius of the circle?

Question 765504: Two parallel chords on opposite sides of the centre of a circle are 9 cm apart. If the chords are 8 cm and 12 cm long, then what is the radius of the circle?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Two parallel chords on opposite sides of the centre of a circle are 9 cm apart. If the chords are 8 cm and 12 cm long, then what is the radius of the circle?
***
I don't have the means to draw the sketch, but I can try to describe it to you. I am working with two right triangles. Both triangles have the radius as the hypotenuse with a known leg=1/2 of the length of the respective chords (4 and 6 cm). The sum of the unknown legs=distance(9cm) between the given chords.
r=radius
..

square both sides

square both sides again
r^2-36=11.48
r^2=36+11.48=47.48
r=√47.48
r=6.89 cm
RELATED QUESTIONS
Two parallel chords on opposite sides of the centre of a circle are 9 cm apart. If the... (answered by ankor@dixie-net.com)

Two parallel chords on the same side of the centre of a circle are 5 cm apart. If the... (answered by Edwin McCravy)

Two parallel chords 16 cm and 30 cm long are 23cm apart. What is the radius of the... (answered by scott8148)

two parallel chords lie on opposite sides of the centre of a circle of radius 13cm. their (answered by Boreal)

two parallel chords of length 30 cm and 16 cm are draw on the opposite sides of center of (answered by ikleyn)

in a circle of radius 20 cm the distance between a pair of equal and parallel chords is... (answered by pedjajov)

Pleas help me to solve this question: AB and CD are two parallel chords of a circle. If... (answered by Seutip,Edwin McCravy)

two parallel chords, 16 cm and 30 cm are 23 cm apart. find the radius of the circle that... (answered by fractalier)

Two parallel chord lies on opposite sides of the centre of a circle of diameter 24cm.the... (answered by josgarithmetic)