SOLUTION: Hi there! I am having trouble attempting to solve this question. Graph the circle x^2+y^2-4x+2y-4=0. Thanks for viewing.

Algebra.Com
Question 756770: Hi there! I am having trouble attempting to solve this question. Graph the circle x^2+y^2-4x+2y-4=0.
Thanks for viewing.

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
I am having trouble attempting to solve this question. Graph the circle x^2+y^2-4x+2y-4=0.
---------------
It's not a question, it's an equation.
Graphing it is not solving it.
------
Graph the circle x^2+y^2-4x+2y-4=0

Complete the squares for x and y


The center is (-2,-1)
The radius = 3

RELATED QUESTIONS

Hi there! I am having trouble remembering how to do this problem. Convert the equation... (answered by stanbon)
Hi there! I am having trouble solving this question. Find all solutions to the equation.... (answered by Alan3354)
Hi there! I am having trouble solving this problem. Convert r=2csc(theta) into... (answered by rothauserc)
Hi, I am having trouble on this question... Write an equation of the line containing... (answered by nerdybill)
Hi. I am having so much trouble with this one questions. I don't understand graphing... (answered by mananth)
I am having trouble with the following question, please help. {{{sqrt(16x-4)= 4x-2}}}... (answered by Theo)
Good Evening! I am having trouble with this problem: Sketch the graph of the... (answered by mananth)
Hi, I'm having a spot of trouble with the below question: Find the points of... (answered by josmiceli)
I am having trouble with the problem right here attempting to figure it out. Graph:... (answered by Fombitz)