SOLUTION: Hi there! I am having trouble attempting to solve this question. Graph the circle x^2+y^2-4x+2y-4=0.
Thanks for viewing.
Algebra.Com
Question 756770: Hi there! I am having trouble attempting to solve this question. Graph the circle x^2+y^2-4x+2y-4=0.
Thanks for viewing.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
I am having trouble attempting to solve this question. Graph the circle x^2+y^2-4x+2y-4=0.
---------------
It's not a question, it's an equation.
Graphing it is not solving it.
------
Graph the circle x^2+y^2-4x+2y-4=0
Complete the squares for x and y
The center is (-2,-1)
The radius = 3
RELATED QUESTIONS
Hi there! I am having trouble remembering how to do this problem. Convert the equation... (answered by stanbon)
Hi there! I am having trouble solving this question. Find all solutions to the equation.... (answered by Alan3354)
Hi there! I am having trouble solving this problem. Convert r=2csc(theta) into... (answered by rothauserc)
Hi, I am having trouble on this question...
Write an equation of the line containing... (answered by nerdybill)
Hi. I am having so much trouble with this one questions. I don't understand graphing... (answered by mananth)
I am having trouble with the following question, please help.
{{{sqrt(16x-4)= 4x-2}}}... (answered by Theo)
Good Evening! I am having trouble with this problem:
Sketch the graph of the... (answered by mananth)
Hi,
I'm having a spot of trouble with the below question:
Find the points of... (answered by josmiceli)
I am having trouble with the problem right here attempting to figure it out.
Graph:... (answered by Fombitz)