SOLUTION: Find the equation of the circle that is tangent to the line x-1=0 and x-6=0, and passes through the point (2,2).

Question 750706: Find the equation of the circle that is tangent to the line x-1=0 and x-6=0, and passes through the point (2,2).
Answer by tommyt3rd(5050) (Show Source): You can put this solution on YOUR website!
since our two lines are parallel, the circle's diameter must be 6-1=5 (and so r=5/2)
This means that the x-coordinate of the center must 1+5/2=7/2
Next we can write:

after solving we determine that k=0.
therefore...

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