SOLUTION: what are the coordinates of the center of the circle whose equation is (x-3)^2+(y+7)^2=36?

Question 748722: what are the coordinates of the center of the circle whose equation is (x-3)^2+(y+7)^2=36?
Found 2 solutions by Cromlix, stanbon:
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Formula for a circle:
(x - a)^2 + (y - b)^2 = r^2
(x-3)^2+(y+7)^2=36
Therefore the coordinates of the circle
is (3, -7)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
what are the coordinates of the center of the circle whose equation is (x-3)^2+(y+7)^2=36?
---
Ans: (3,-7)
==============
Cheers,
Stan H.
=============
RELATED QUESTIONS
What are the coordinates of the center and the measure of a radius of the circle whose... (answered by Boreal)
In the standard (x,y) coordinate plane, what are the coordinates of the center of the... (answered by KMST)
What is the sum of the coordinates of the center of the circle whose equation is x^2 + (answered by stanbon,mananth,ewatrrr)
The equation below describes a circle. What are the coordinates of the center of the... (answered by Alan3354)
What are the center and radius of the circle whose equation is x2 + (y-3)2 =... (answered by Cromlix)
What is the center of a circle whose equation is (x - 1)2 + (y + 3)2 =... (answered by Alan3354)
2. For the circle with equation (x � 2)2 + (y + 3)2 = 9, answer each question: a) What... (answered by ewatrrr)
2. For the circle with equation (x + 3)2 + (y � 2)2 = 16, answer each question: a.)... (answered by richwmiller)