SOLUTION: What is the equation of a circle touching the lines x-3y-11=0 and 3x-y-9=0 and having its center on the line x-2y+19=0 ?

Question 743928: What is the equation of a circle touching the lines x-3y-11=0 and 3x-y-9=0 and having its center on the line x-2y+19=0 ?

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
What is the equation of a circle touching the lines x-3y-11=0 and 3x-y-9=0 and having its center on the line x-2y+19=0 ?
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Find the bisector of the 2 lines that are tangent.
The intersection of the bisector and x-2y+19=0 is the center of the circle.
The radius of the circle is the distance from the center to either of the tangent lines.
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This is a multi-step problem. I've done it once or twice.
email via the TY note for help or to check your work.

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