SOLUTION: Find the centre and radius of the circle given by equation:x^2+y^2-6y+8=0 is this question missing an x how is this done?

Question 732404: Find the centre and radius of the circle given by equation:x^2+y^2-6y+8=0
is this question missing an x how is this done?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the centre and radius of the circle given by equation:x^2+y^2-6y+8=0
is this question missing an x how is this done?
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Note: x^2 is already a perfect square. You don't have to complete it.
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Complete the y-terms.
x^2 + y^2+6y+9 = -8+9
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Factor:
(x-0)^2 + (y-3)^2 = 1
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Center at (0,3)
Radius = sqrt(1) = 1
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Cheers,
Stan H.
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