SOLUTION: Hi, I need help with a circle problem. I can't draw it so I'll explain it thoroughly. The circle has a center point of R. There are two chords running through it looking slightl

Question 728811: Hi, I need help with a circle problem. I can't draw it so I'll explain it thoroughly.
The circle has a center point of R. There are two chords running through it looking slightly parallel, but they are not. the intersection of them lies with two small line segments, one end on a chord and the other end on the center point R. the two intersections are perpendicular to the chord. One segment is 6 the other is x. The chord lengths are 26 and 24. The left chord is 26, the left intersection is 6. The right chord is 24, and the right intersection is x.
I have tried so many different ways and I'm sad to say the closest answer I got was 5.5, not one of the choices. The other successful way I tried was 24/4 = 26/x but I honestly don't think that's correct. I got 6.5 which is one of the answers.
Please help and Thank You!

Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Yes, the ratio of the measure of the longer chord to the measure of the shorter chord is equal to the ratio of the measure of the shorter perpendicular to the longer perpendicular, in other words:

Which is equivalent to the proportion you had (once the typo was corrected) since you can interchange the means on a proportion.

John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it

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