SOLUTION: find the (h,k) and radius r for the equation 4(x-5)^2+4y^2=16. What are the intercepts?

Question 719633: find the (h,k) and radius r for the equation 4(x-5)^2+4y^2=16. What are the intercepts?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
find the (h,k) and radius r for the equation 4(x-5)^2+4y^2=16.
(x-5)^2 + y^2 = 4
(h,k) = (5,0) the center
r^2 = 4 --> r = 2
--------
What are the intercepts?
(x-5)^2 + y^2 = 4
y=0: --> (x-5)^2 = 4
x - 5 = 2
x = 7 --> (7,0)
---
x-5 = -2
x = 4 --> (3,0)
---
x=0: --> 25 + y^2 = 4
y^2 = -21 --> no y-intercepts
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