SOLUTION: find the center radius form of the equation of a circle with the center(2,8) and tangent to the x axis

Question 718623: find the center radius form of the equation of a circle with the center(2,8) and tangent to the x axis
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
If the center is at (2,8), and it is tangent to the x axis, this means that it just barely touches the x axis from a center that is 8 units above the x-axis. So, the radius of the circle is 8.

(x-h)^2 + (y-k)^2 = r^2
(x-2)^2 + (y-8)^2 = 64

For additional help with circles, you may want to see my non-traditional explanation of this and other topics on my own website: www.mathinlivingcolor.com.

Click on the link at the very bottom of the page which will take you to my Homepage, and look for the link "Basic, Intermediate, and College Algebra: One Step at a Time." Choose "College Algebra" and look in Chapter 2 for the section on Circles. Then, I solved many of my problems IN COLOR, which makes all the difference in the world, to understanding math concepts. Try it for this topic as well as others, and let me know what YOU think.

Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
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