SOLUTION: A chord of length 16 sqrt3 is the perpendicular bisector of the radius in a circle. Determine the area of the circle.Please show me the steps

Question 700877: A chord of length 16 sqrt3 is the perpendicular bisector of the radius in a circle. Determine the area of the circle.Please show me the steps
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A chord of length 16 sqrt3 is the perpendicular bisector of the radius in a circle.
Determine the area of the circle.Please show me the steps
:
We want to find the radius first.
A right triangle is formed by half the chord and half the radius and the radius
The radius is the hypotenuse, therefore using pythag; a^2 + b^2 = c^2
+ =
64(3) + .25r^2 = r^2
192 = r^2 - .25r^2
192 = .75r^2
r^2 = 192/.75
r^2 = 156
r =
r = 16
:
A =
A = 804.2477 sq units
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