SOLUTION: If P is a point on the circle x2+y2=9 and Q is a point on the line 7x+y+3=0 and the line is perpendicular bisector of line PQ, find the coordinet of P.

Question 681863: If P is a point on the circle x2+y2=9 and Q is a point on the line 7x+y+3=0 and the line is perpendicular bisector of line PQ, find the coordinet of P.

Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
I believe something is wrong or missing.
Otherwise it would be sort of a trick question.
Lines do not have bisectors; only segments do.
A perpendicular bisector of segment (not line) PQ is a line that goes through the midpoint of segment PQ, and is perpendicular to PQ.
If Q is a point on the line that is the perpendicular bisector of line PQ, then P, Q, and the midpoint of PQ would all be the same point.
That point would belong to the circle (because it is P), and to the line (because it is Q).

P and Q would be (0,-3) or (-42/50,144/50)
RELATED QUESTIONS
If P is a point on the circle x2+y2=9,Q is a point on the line 7x+y+3=0 and the line... (answered by KMST)

Hello tutor, This one question on my online homework assignment has been puzzling me for (answered by lwsshak3)

The equation of the perpendicular bisector of the line segment joining the points P... (answered by greenestamps)

In triangle ABC, M is the midpoint of line AB. Let D be the point on line BC such that... (answered by math_helper)

Two points have coordinates A(1,-3) and B(-3,5).Find the equation of the perpendicular... (answered by ewatrrr)

Point P is located at (3, 3) and Point Q is located at (1, 1). If Points P, Q and R are... (answered by josgarithmetic,MathTherapy)

A theorem from geometry states that a line passing through the center of a circle and... (answered by josgarithmetic)

1. If p, q, r are three points of a line and the coordinates of p and r are √3 and... (answered by ikleyn)