SOLUTION: For what values of K is y=k a tangent to the circle (x-1)^2+(y+4)^2=25?

Question 67873: For what values of K is y=k a tangent to the circle (x-1)^2+(y+4)^2=25?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
For what values of K is y=k a tangent to the circle (x-1)^2+(y+4)^2=25?
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The equation is that of a circle with center at (1,-4) and radius 5
Draw the picture.
The line you are looking for is parallel to the x-axis and intersects
the circle at its topmost point and its bottommost point.
Topmost is (1,-4+5)=(1,1)
The line would be y=1; k=1
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Bottommost is (1,-4-5)=(1,-9)
The line would be y=-9; k=-9
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Cheers,
Stan H.

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