SOLUTION: what is the center and the equation of x2+y2+16x+6y+9=0

Algebra.Com
Question 650877: what is the center and the equation of x2+y2+16x+6y+9=0
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
x2+y2+16x+6y+9=0
x2+y2+16x+6y = -9 ||Completing the Square
(x+8)^2 + (y + 3)^2 = -9 + 64 + 9
(x+8)^2 + (y + 3)^2 = 64 C (-8,-3), Circle with r = 8
Standard Form of an Equation of a Circle is
where Pt(h,k) is the center and r is the radius

RELATED QUESTIONS

find the center and radius of the circle with equation... (answered by Earlsdon)
What is the equation of the circle passing through the point (6,5) and centered at... (answered by josgarithmetic)
What is the center of the circle given by the equation below? x2 - 16x + y2 - 18y =... (answered by stanbon)
Classify the conic section: 1. x2 + y2 = 36 2. x2 - y2 = 36 3. 5x2 +... (answered by Edwin McCravy)
What is the graph of the equation x2 + y2 - 8x + 6y + 24 =... (answered by Edwin McCravy)
What is the center of the hyperbola whose equation is (x2)/4 - (y2)/9 = 1? (answered by lwsshak3)
What is the general form of the equation of a circle with its center at (-2, 1) and... (answered by josgarithmetic)
. Find the center and radius of the circle whose equation is x2 + y2 – 4 = 0. (answered by Alan3354)
Find the CENTER and the LENGTH of a radius of the circle. x2 + y2 + 16x + 4y + 59 =... (answered by robertb,stanbon)