SOLUTION: find the coordinates of the center and radius of the circle by the equation x^2+y^2+½x-3y=27/16=0

Algebra.Com
Question 630530: find the coordinates of the center and radius of the circle by the equation x^2+y^2+½x-3y=27/16=0
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Assuming You meant:
x^2+y^2+ 1/2x-3y+27/16=0 completing the Square

C(-.25, 1.5) and r = /4
RELATED QUESTIONS

Prove that the equation: X^2+Y^2-6X=0 is an equation of a circle and find the coordinates (answered by josgarithmetic)
Find the center and radius of the circle given by the equation x^2 + y^2 - 8x + 2y - 11 = (answered by nerdybill)
Find the center and radius of the circle given by the equation... (answered by stanbon)
Write the equation of the circle in standard form find the center, radius, intercepts and (answered by lwsshak3)
find the center and the radius of the circle.... (answered by stanbon)
What are the coordinates of the center and the measure of a radius of the circle whose... (answered by Boreal)
Find the center and radius of the circle. (x-2)^2 +... (answered by Earlsdon)
Find the center and radius of the circle. (x-2)^2 +... (answered by solver91311)
find the center and the radius of the circle whose equation is (x-3)^2 + (y+2)^2 = 16 (answered by Fombitz)