SOLUTION: find the coordinates of the center and radius of the circle by the equation x^2+y^2+½x-3y=27/16=0
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Question 630530
:
find the coordinates of the center and radius of the circle by the equation x^2+y^2+½x-3y=27/16=0
Answer by
ewatrrr(24785)
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Hi,
Assuming You meant:
x^2+y^2+ 1/2x-3y+27/16=0 completing the Square
C(-.25, 1.5) and r =
/4
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