SOLUTION: Endpoints of a diameter: (-1, -6) (1, 6)

Question 627051: Endpoints of a diameter: (-1, -6) (1, 6)
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
I'm assuming you want to find the equation of the circle.

Recall that the general equation of a circle is .

So we need the center (h,k) and the radius squared .

First, let's find the center (h,k).

Since the center is the midpoint of the line segment with endpoints (-1,-6) and (1,6), we need to find the midpoint.

X-Coordinate of Midpoint =

Since the x coordinate of midpoint is , this means that

Y-Coordinate of Midpoint =

Since the y coordinate of midpoint is , this means that

So the center is the point (0, 0)

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Now let's find the radius squared

Use the formula , where (h,k) is the center and (x,y) is an arbitrary point on the circle.

In this case, and . Also, and . Plug these values into the equation above and simplify to get:

So because , , and , this means that the equation of the circle that passes through the points (-1,-6) and (1,6) (which are the endpoints of the diameter) is

.

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