SOLUTION: A circle has its center at the center of a square with 12-inch sides. Using 3.14 for pi, find the area of the square not covered by the circle, then write a ratio of the circle�s c

Question 625348: A circle has its center at the center of a square with 12-inch sides. Using 3.14 for pi, find the area of the square not covered by the circle, then write a ratio of the circle�s circumference to the perimeter of the square.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A circle has its center at the center of a square with 12-inch sides. Using 3.14 for pi, find the area of the square not covered by the circle
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Area of the square = 12*12 = 144 sq inches
Area of the circle = sq inches
--> 144 - 36pi sq inches
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then write a ratio of the circle�s circumference to the perimeter of the square.
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Sq P = 4*12 = 48
C = 2*pi*r = 12pi
--> 12pi/48
= pi/4

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