# SOLUTION: What is the center and the radius of a circle whose equation is x^2+y^2 -4x +14y +28=0 ?

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 Question 616356: What is the center and the radius of a circle whose equation is x^2+y^2 -4x +14y +28=0 ?Answer by lwsshak3(6490)   (Show Source): You can put this solution on YOUR website!What is the center and the radius of a circle whose equation is x^2+y^2 -4x +14y +28=0 ? complete the square x^2 -4x+y^2+14y +28=0 (x^2-4x+4)+(y^2+14y+49)=-28+4+49 (x-2)^2+(y+7)^2=25 Standard form of equation for a circle: (x-h)^2+(y-k)^2=r^2, (h,k)=(x,y) coordinates of center, r=radius For given equation: center:(2,-7) r^2=251 r=√25=5