# SOLUTION: what is the general form of the equation of a circle below (x-4)^2+y^2=16 1)x^2+y^2-8x-16=16 2)x^2+y^2-8x+16=16 3)x^2+y^2-8x=0 4)x^2+y^2+8x=0

Algebra ->  Algebra  -> Circles -> SOLUTION: what is the general form of the equation of a circle below (x-4)^2+y^2=16 1)x^2+y^2-8x-16=16 2)x^2+y^2-8x+16=16 3)x^2+y^2-8x=0 4)x^2+y^2+8x=0      Log On

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 Click here to see ALL problems on Circles Question 614579: what is the general form of the equation of a circle below (x-4)^2+y^2=16 1)x^2+y^2-8x-16=16 2)x^2+y^2-8x+16=16 3)x^2+y^2-8x=0 4)x^2+y^2+8x=0Answer by ewatrrr(10682)   (Show Source): You can put this solution on YOUR website! ``` Hi, what is the general form of the equation of a circle below (x-4)^2+y^2=16 1)x^2+y^2-8x-16=16 2)x^2+y^2-8x+16=16 3)x^2+y^2-8x=0 || (x-4)^2 - 16 + y^2 = 0 or (x-4)^2 + y^2 = 16 4)x^2+y^2+8x=0 ```