SOLUTION: what is the general form of the equation of a circle below (x-4)^2+y^2=16 1)x^2+y^2-8x-16=16 2)x^2+y^2-8x+16=16 3)x^2+y^2-8x=0 4)x^2+y^2+8x=0

Algebra ->  Algebra  -> Circles -> SOLUTION: what is the general form of the equation of a circle below (x-4)^2+y^2=16 1)x^2+y^2-8x-16=16 2)x^2+y^2-8x+16=16 3)x^2+y^2-8x=0 4)x^2+y^2+8x=0      Log On

Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 614579: what is the general form of the equation of a circle below
(x-4)^2+y^2=16
1)x^2+y^2-8x-16=16
2)x^2+y^2-8x+16=16
3)x^2+y^2-8x=0
4)x^2+y^2+8x=0
Answer by ewatrrr(10682) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

what is the general form of the equation of a circle below

 (x-4)^2+y^2=16 

1)x^2+y^2-8x-16=16

 2)x^2+y^2-8x+16=16

 3)x^2+y^2-8x=0    || (x-4)^2 - 16 + y^2 = 0  or (x-4)^2 + y^2 = 16

 4)x^2+y^2+8x=0