SOLUTION: what is the equation of a circle having radius of 5 and tangent to both axes?

Question 601804: what is the equation of a circle having radius of 5 and tangent to both axes?
Found 2 solutions by jim_thompson5910, Alan3354:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
If it has a radius of 5 and the circle is tangent to both axes, then the center must be 5 units away from both axes. So the center is (h,k) = (5,5). The radius is 5, so r = 5.

So the equation in the form is
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
what is the equation of a circle having radius of 5 and tangent to both axes?
--------
There are 4 possible circles, one in each quadrant.
The radius is 5.
The center is (5,5), (-5,5), (-5,-5) & (5,-5)
The eqn is

where (h,k) is the center.

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