SOLUTION: if the center of a circle is at the point (-2,8) and the circle goes through the origin, whats the radius

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Question 527857: if the center of a circle is at the point (-2,8) and the circle goes through the origin, whats the radius
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(30993) About Me  (Show Source):
You can put this solution on YOUR website!
The radius is the distance from (-2,8) to (0,0)
r+=+sqrt%28%28-2%29%5E2+%2B+8%5E2%29
r+=+sqrt%2868%29+=+2sqrt%2817%29

Answer by stanbon(57290) About Me  (Show Source):
You can put this solution on YOUR website!
if the center of a circle is at the point (-2,8) and the circle goes through the origin, whats the radius
----
Distance from (0,0) to (-2,8)
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d = sqrt[2^2+8^2] = sqrt(68) = 2*sqrt(17)
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Cheers,
Stan H.