SOLUTION: -x^2-y^2+10x+12y-36=0

Question 450593: -x^2-y^2+10x+12y-36=0
Answer by rwm(914) (Show Source): You can put this solution on YOUR website!
That is a lovely equation with two unknowns.
There is no solution because there are two unknowns.
So what is your question?
-x^2-y^2+10x+12y-36=0
-(x-5)^2-(y-6)^2+25 = 0
(x-5)^2+(y-6)^2=25
(1/25(x-5)^2)+(1/25 (y-6)^2) = 1

RELATED QUESTIONS
x^2+12x+y^2+12y+36=0 (answered by Edwin McCravy)

What is the standard form of, x^2 + 10x + 45 + y^2 + 12y = 0 (answered by Jeff Gordon)

x^2-10x+36=0 (answered by Fombitz)

Find the center of a circle defined by the equation:... (answered by ewatrrr)

x^2+y^2=169... (answered by Fombitz)

x^2 + y^2 + 14x + 12y + 84=0 (answered by ewatrrr)

x^2 + y^2 - 4x +12y - 20 = 0 (answered by Fombitz,ikleyn,Alan3354)

find the center and radius of the circle given by:... (answered by Earlsdon)

find the center and radius of the circle given by:... (answered by scott8148)