SOLUTION: I need to know the radius and center for this equation. It is for cirles. 4x^2+75x-35y+4y^2=0

Question 44490: I need to know the radius and center for this equation. It is for cirles.
4x^2+75x-35y+4y^2=0
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
I need to know the radius and center for this equation. It is for cirles.
4x^2+75x-35y+4y^2=0
=4(X^2+75X/4-35Y/4 +Y^2)=0
=[(X)^2+2(X)(75/8)+(75/8)^2]-(75/8)^2+[Y^2-2(Y)(35/8)+(35/8)^2]-(35/8)^2=0
=[X+(75/8)]^2+[Y-(35/8)]^2=(75^2+35^2)/64=6850/64={82.67/8}^2
COMPARING WITH STD.EQN.
(X-H)^2+(Y-K)^2=R^2...WE GET
CENTRE AS (-75/8,35/8)AND RADIUS AS (82.67/8)=10.33
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